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Simon Glass authored
Sandbox doesn't actually provide U-Boot access to the machine's physical memory. Instead it provides a RAM buffer of configurable size, and all memory accesses are within that buffer. Sandbox memory starts at 0 and is CONFIG_DRAM_SIZE bytes in size. Allowing access outside this buffer might produce unpredictable results in the event of an error, and would expose the host machine's memory architecture to the sandbox U-Boot. Most U-Boot functions assume that they can just access memory at given address. For sandbox this is not true. Add a map_sysmem() call which converts a U-Boot address to a system address. In most cases this is a NOP, but for sandbox it returns a pointer to that memory inside the RAM buffer. To get a U-Boot feature to work correctly within sandbox, you should call map_sysmem() to get a pointer to the address, and then use that address for any U-Boot memory accesses. Signed-off-by:Simon Glass <sjg@chromium.org>
Simon Glass authoredSandbox doesn't actually provide U-Boot access to the machine's physical memory. Instead it provides a RAM buffer of configurable size, and all memory accesses are within that buffer. Sandbox memory starts at 0 and is CONFIG_DRAM_SIZE bytes in size. Allowing access outside this buffer might produce unpredictable results in the event of an error, and would expose the host machine's memory architecture to the sandbox U-Boot. Most U-Boot functions assume that they can just access memory at given address. For sandbox this is not true. Add a map_sysmem() call which converts a U-Boot address to a system address. In most cases this is a NOP, but for sandbox it returns a pointer to that memory inside the RAM buffer. To get a U-Boot feature to work correctly within sandbox, you should call map_sysmem() to get a pointer to the address, and then use that address for any U-Boot memory accesses. Signed-off-by:
