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xypron.glpk@gmx.de authored
'A || (!A && B)' is equivalent to 'A || B'. Let's reduce the complexity of the statement in start_jr0(). The problem was indicated by cppcheck. Signed-off-by:
Heinrich Schuchardt <xypron.glpk@gmx.de> Reviewed-by:
York Sun <york.sun@nxp.com> Reviewed-by:
Simon Glass <sjg@chromium.org>
xypron.glpk@gmx.de authored'A || (!A && B)' is equivalent to 'A || B'. Let's reduce the complexity of the statement in start_jr0(). The problem was indicated by cppcheck. Signed-off-by:
